CS401 - Computer Architecture and Assembly Language Programming Assignment No. 1 Solution and Discussion Spring 2015 Due Date: May 20, 2015

CS401 Assembly language

Question No.1:

Solution:

1.      BX+SI+0xFF00

By adding these registers we get effective address

BX+SI+0xFF00

0x is offset

0000

+01A2

+FF00

=166A0

Physical Address

DX is the default of BX

BX=DXx10

=0A2Ex10

=0A2E0

Adding all registers again

0A2E0+166A0=26A40

This is the physical address.

2.      BP+DI+0xA000

By adding these registers we get effective address

BP+DI+0xA000

0x is offset

0000

+000A

+A000

A00A

Physical Address

BP is the default value of SS

BP=SSx10

BP=12A1x10

BP=12A10

Add all registers again

12A10+A00A=1CA1A

Question No.2:

 www.vusuperior.net

Solution:

Code:

[org 0x0100]

MOV CX, 5 ; DECIMAL MOVE 5

MOV BP, P_NUM ; PUTING ADDRESS OF P_NUM TO BP
MOV AX, [BP] ; FIST ELEMENT TO AX

ADD BP, 6 ; MOVING ON 4RTH ELEMENT OF P_NUM

MOV BX, [BP]

ADD BP, 2

MOV DX, [BP]

ADD AX, BX

ADD AX, DX

MOV DX, AX

MOV AX, 0X0C400
INT 0X21

P_NUM DW 2, 3, 5, 7, 11